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沙痕
給生活編個(gè)程序,讓你過(guò)得更精彩~!
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樓主  發(fā)表于: 2012-07-05 14:12
比如有4個(gè)輸入點(diǎn),接的是4個(gè)常開(kāi)點(diǎn)的開(kāi)關(guān),X1、X2、X3、X4;X1和X3,X2和X4是同時(shí)動(dòng)作的,X1或者X3都能控制輸出Y0,X2或者X4都能復位Y0;等于原本只是一個(gè)點(diǎn)控制輸出,一個(gè)點(diǎn)復位,現在為了保險,多并一組上去吧;問(wèn)題來(lái)了,如何判斷X1、X2、X3、X4在這個(gè)過(guò)程中有任意一個(gè)點(diǎn)不動(dòng)作或者都不接,然后輸出報警點(diǎn)Y1(加個(gè)說(shuō)明,本應該同時(shí)動(dòng)作的,可是因為各種原因,動(dòng)作可能會(huì )有一兩秒的誤差,算作正常處理)
[ 此帖被774813500在2012-07-05 16:11重新編輯 ]
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1樓  發(fā)表于: 2012-07-05 18:12
圖片:
不知這是不是你要的。

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