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hua966
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樓主  發(fā)表于: 2013-09-21 15:38
   論壇里面的大蝦，本人做工控多年了，對伺服不是很了解，
  假設：電機額定轉速：2000RPM
 電機輸出側減速機：1：10
電機輸出側主動(dòng)輪直徑：80MM
伺服編碼器開(kāi)辨率：262144  18位
PLC最大輸出脈沖：100K HZ
      1：求師傅們幫我解釋一下伺服的最高線(xiàn)速度；
      2：電機轉一周，所需要PLC脈沖數；
    解釋最好有公式，本人在此先謝過(guò)了！
baiqrmai
承接各行業(yè)生產(chǎn)線(xiàn)改造，編程，自動(dòng)化研發(fā)、制造，配
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1樓  發(fā)表于: 2013-09-21 17:29
電機轉一周 要262144個(gè)脈沖    還有你都沒(méi)有一螺距啊怎么去談速度
承接各行業(yè)自動(dòng)化設備維修.改造，伺服，步進(jìn)，PLC，觸摸屏編程，上位機設計電氣制做，各種自動(dòng)化工程安裝，電柜制作。陳工13530398214

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