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hyjx111
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樓主  發(fā)表于: 2015-11-10 20:30
在梯形圖中MOV C0  K4M10對應后面的常開(kāi)觸點(diǎn)M12、MOV C1   K4M30對應后面的常開(kāi)觸點(diǎn)M33、MOV C2   K4M50對應后面的常開(kāi)觸點(diǎn)M54、CMOV 3  K4M70對應后面的常開(kāi)觸點(diǎn)M75是怎么理解呢?C0=2時(shí) M12應該是0、C1=3時(shí) M33應該是0、C2=4時(shí) M54應該是0、C3=5時(shí) M75應該是0,什么狀態(tài)下能將M12、M33、M54、M75都為1呢?
[ 此帖被hyjx111在2015-11-15 22:05重新編輯 ]
liaohianbin
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1樓  發(fā)表于: 2015-11-11 09:24
M12要C=4才為1,M33要C=8才為1,M54要C=16為1,M75要C=32才為1
[ 此帖被liaohianbin在2015-11-11 11:29重新編輯 ]

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