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yb6byl
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樓主  發(fā)表于: 2017-11-30 09:56
[upload=1] 在電網(wǎng)電壓正半波期間，D1導通，C1充電電流經(jīng)穩壓處理流入負載電路；電網(wǎng)電壓負半波期間，D1截止D2導通，將C1內部所充電荷釋放干凈；我這個(gè)電路的正半波期間的電流走向是可以看懂得，但是在負半波期間的電流走向就不是很明白，尤其是c1內的充電荷是如何釋放出去的？如果把D2拆掉，C2的充電荷還會(huì )釋放掉嗎？不會(huì )，為什么不會(huì )？
sjbandmm
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1樓  發(fā)表于: 2017-12-01 18:24
如果D2拆除，那么D1回路就只有半波，也就是直流了，C1充電后就沒(méi)法釋放，那么也就沒(méi)有電流流過(guò)負載了；
本電路是電容降壓電路，利用電容的容抗來(lái)限制負載電流，1UF電容在220V/50HZ電源負載下約產(chǎn)生72mA電流。電容降壓要根據負載電流和電源電壓和頻率選擇C1.

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