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吳曉亮420922
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樓主  發(fā)表于: 2018-03-29 08:49
圖片:
在A(yíng)處檢測,需要到B處剔除,請問(wèn)用什么編程邏輯?
如圖,紙箱在封箱機后面檢測到不合格,經(jīng)過(guò)兩個(gè)光電,再經(jīng)過(guò)稱(chēng)重線(xiàn),到達剔除機構。需要把在封箱機處檢測不合格的產(chǎn)品剔除,請問(wèn)邏輯上怎么處理呢?
(老是剔除錯誤,把正常的箱剔除了,檢測不合格的箱放過(guò)去了。)
njshenxian
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1樓  發(fā)表于: 2018-03-29 21:42
引用
引用第8樓xuzhanily于2018-03-29 16:02發(fā)表的  :
有兩種做法可以實(shí)現:
1.使用延時(shí)繼電器來(lái)實(shí)現的,就是在A(yíng)處檢測到不良,就啟動(dòng)延時(shí)繼電器,剛好到達B點(diǎn),延時(shí)時(shí)間到啟動(dòng)推除機構,
2.將檢測的每個(gè)產(chǎn)品帶上數據進(jìn)行位移,這樣到達B點(diǎn)就可知道是否需要推除.然后把數據清掉,這樣就可以實(shí)現了
以前有做過(guò)這樣的項目,希望能幫到你!

1是不可靠的,萬(wàn)一產(chǎn)線(xiàn)停頓下,就抓瞎了。
2可以弄弄,把檢測位的放在一個(gè)8位的Byte數據里置為1,(看后續的位置多少,字節8個(gè)不夠就用16位的Word)。然后移位,在剔除位做1判斷。然后,你懂了

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