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樓主  發(fā)表于: 2019-04-21 10:14
圖片:


FOR #a[1] :=1  TO 4 DO
        #a[5] := #a[1] + #a[1];
        #c := 1 + #c;

        #a[2] := 1+ #a[2];
        #a[4] := 4;

        IF #start_1 = 1 THEN
            
            ;
        END_IF;
        #a[5] := 5;
      
        ;
    END_FOR;

在編寫(xiě)的一個(gè)for循環(huán)中,用數組a{2}定義了一個(gè)int整數進(jìn)行自加1(其初始值為0),即:a{2}:=1+a{2};當for循環(huán)第一次,執行到自加語(yǔ)句的時(shí)候,其a{2}的結果應當是1啊,怎么這么多啊,就跟梯形圖里的add指令一樣,一接通使能,每個(gè)掃描周期加一次。而java語(yǔ)言里,for循環(huán)執行一次就加一次。求教如何使for循環(huán),每循環(huán)一次,自加的時(shí)候,語(yǔ)句只加一次呢
cvlsam
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1樓  發(fā)表于: 2019-04-21 15:46
因為start=1,那么每個(gè)掃描周期都在執行for循環(huán)………………

這不是SCL的坑,是程序員自己挖的坑啊,你這個(gè)程序,在JAVA中也是這個(gè)狀態(tài),你這個(gè)程序,在JAVA中不就是

while(start){
    for(int a[1]=1;a[1]<5;a[1]++){};
}

當start=1的時(shí)候………………

Good Luck~

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