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樓主  發(fā)表于: 2020-09-09 11:59
/*已知原坐標A1(Xa1,Ya1),B1(Xb1,Yb1),C1(Xc1,Yb1)
原產(chǎn)品經(jīng)過(guò)擺動(dòng)后,新坐標為
偏移量,ΔX,ΔY

2點(diǎn)拍照,得出A2(Xa2,Ya2),B2(Xb2,Yb2)

求C點(diǎn)新坐標C2(Xc2,Yc2)

K1=(Ya1-Yb1)/(Xa1-Xb1)
K2=(Ya2-Yb2)/(Xa2-Xb2)
第一步
利用夾角公式,求得tan&的值。
tan&=|(k1-k2)/(1+k1*k2)|

K1-K2>0,在原圖像上進(jìn)行順時(shí)針旋轉偏移,即Tan&為正值
K1-K2<0,在原圖像上進(jìn)行逆時(shí)針旋轉偏移,即Tan&為負值

利用兩點(diǎn)確立的直線(xiàn)在坐標系中,斜率想減的值,確認&為正值還是負值
確定&是正角度偏移或負角度偏移,即tan&取正值還是負值

第二步

TAN&為已知,則弧度=ARCTAN&
那么SIN&=SIN(arctan&)
    COS&=COS(arctan&)
    /
    
第三步
由最初A1,B1,C1.
到|AC|=√[(Xa1-Xc1)^2+(Ya1-Yc1)^2]

那么C2的坐標Xc2=(COS&*|AC|)+Xa2
            Yc2=SIN&*|AC|+Ya2

    
總結,1,根據已知坐標值,求得圖像旋轉偏移角度(弧度)值,
      2,已知坐標,求得第三點(diǎn)基于已知點(diǎn)的關(guān)系,兩點(diǎn)線(xiàn)段長(cháng)度
      3,推到得出改變后第三點(diǎn),相對于改變后已知點(diǎn)的,坐標值
      
      */
DATAN(TRUE, 1, TEMP1 );
DSIN(TRUE,TEMP1,D1000:E);
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